Resonance and the superforce

doi:10.15406/oajmtp.2018.01.00025

Open Access Journal of

eISSN: 2641-9335

Mathematical and Theoretical Physics

Opinion Volume 1 Issue 4

Resonance and the superforce

Paul TE Cusack

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Park Ave, Saint John, Canada

Correspondence: Paul TE Cusack, BScE, Dule 23 Park Ave,Saint John, NB E2J 1R2, Canada, Tel 5066 5263 50

Received: June 22, 2018 | Published: August 9, 2018

Citation: Paul TEC. Resonance and the superforce. Open Acc J Math Theor Phy. 2018;1(4):152-153. DOI: 10.15406/oajmtp.2018.01.00025

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Abstract

In this brief paper, we provide some calculations from Wave mechanics, namely Resonance. We see that the universe is stoked by the superforce, and that energy is dampened by the mass. When taken with gravity, the characteristic equation for the universe results.

Keywords: superforce, astrotheology, resonance, golden mean equation

Introduction

Using variables calculated in this author’s previous papers, we derive the characteristic equation for the universe working with the formulas that are used to determine resonance conditions.^1,2

$t a n δ = [1 / Q] / [(ω_{0} / ω) - (ω / ω_{0})]$ $t a n δ = [1 / Q] / [(ω_{0} / ω) - (ω / ω_{0})]$

$δ = π / 4$ $δ = π / 4$ (phase angle)

Q=1/2

Therefore $ω = ω_{0} = 1$ $ω = ω_{0} = 1$

$A = F_{0} / k {[ω ω_{0}] / {[(ω_{0} / ω) - (ω / ω_{0})]}^{2} + (1 / Q^{2})]}^{1 / 2}$ $A = F_{0} / k {[ω ω_{0}] / {[(ω_{0} / ω) - (ω / ω_{0})]}^{2} + (1 / Q^{2})]}^{1 / 2}$

F=8/3

k=0.4233

$ω = ω_{0} = 1$ $ω = ω_{0} = 1$

Q=1/2

Therefore $A = 125.99 \sim 126 = E_{m i n}$ $A = 125.99 \sim 126 = E_{m i n}$

$E_{m i n} 1587 = 1 - s i n 1 = M o m e n t .$ $E_{m i n} 1587 = 1 - s i n 1 = M o m e n t .$

1-0.1587=8425

1/0.8425=118.87 = Mass Periodic Table of the elements.

$ω_{m} = (1) {(1 - 1 / {[2 (1 / 2))}^{2}]}^{1 / 2}$ $ω_{m} = (1) {(1 - 1 / {[2 (1 / 2))}^{2}]}^{1 / 2}$

$= \sqrt{(- 1)}$ $= \sqrt{(- 1)}$

=-0.618

$ω_{0} < ω_{m}$ $ω_{0} < ω_{m}$

Therefore, $α = π$ $α = π$

$A_{m} = A_{0} = 1 / 2 / [1 - 4 {(1 / 2)}^{2}]$ $A_{m} = A_{0} = 1 / 2 / [1 - 4 {(1 / 2)}^{2}]$

$= A_{0} 1 / 0$ $= A_{0} 1 / 0$

$= \infty$ $= \infty$

$ω_{m} = ω_{0} {{1 - 1 / (2 Q^{2})]}^{1 / 2}$ $ω_{m} = ω_{0} {{1 - 1 / (2 Q^{2})]}^{1 / 2}$

$ω_{m} / ω_{0} = 0.935$ $ω_{m} / ω_{0} = 0.935$

=mp+

$A_{m} = A_{0} [Q] / {[1 - 1 / 4 Q^{2}]}^{1 / 2}$ $A_{m} = A_{0} [Q] / {[1 - 1 / 4 Q^{2}]}^{1 / 2}$

$A_{m} / A_{0} = 2.06$ $A_{m} / A_{0} = 2.06$

$= γ$ $= γ$

=dM/dt

$ω / ω_{0} = {(1 - 1 / 2 Q^{2})}^{1 / 2}$ $ω / ω_{0} = {(1 - 1 / 2 Q^{2})}^{1 / 2}$

=0.935

$= 1 - 1 / 2 Q^{2} = {(0.938.7)}^{2}$ $= 1 - 1 / 2 Q^{2} = {(0.938.7)}^{2}$

$1 - 1 / 2 Q^{2} = 88.12$ $1 - 1 / 2 Q^{2} = 88.12$

$1 / 2 Q^{2} = 118.72$ $1 / 2 Q^{2} = 118.72$

$1 / Q^{2} = 23.65$ $1 / Q^{2} = 23.65$

$Q = 0 / .1537 = 1 / 6.5 = 1 / G$ $Q = 0 / .1537 = 1 / 6.5 = 1 / G$

$Q = 0.1537 = 1 / 6.50 ~ 1 / G_{0}$ $Q = 0.1537 = 1 / 6.50 ~ 1 / G_{0}$

$ω_{m} / ω_{0} = (1 - 1 / 2 G^{2}) = M p +$ $ω_{m} / ω_{0} = (1 - 1 / 2 G^{2}) = M p +$

$G_{0} / | D e t . | = \sqrt{3} \sqrt{M P +}$ $G_{0} / | D e t . | = \sqrt{3} \sqrt{M P +}$

$G_{0} / M p + = | D | \sqrt{3}$ $G_{0} / M p + = | D | \sqrt{3}$

$| D | = 4$ $| D | = 4$

$G_{0} / M p + = 6928 (938) = 6.50 \sim G_{0}$ $G_{0} / M p + = 6928 (938) = 6.50 \sim G_{0}$

$1 / 6.928 = 1443 = 1 - L n π$ $1 / 6.928 = 1443 = 1 - L n π$

$G_{0} = {1 / (1 - L n π)] M p +$ $G_{0} = {1 / (1 - L n π)] M p +$

$1 / (1 - L n π) = 1 / - t = - E$ $1 / (1 - L n π) = 1 / - t = - E$

$G_{0} = 1 / t (1 - 1 / 2 G^{2})$ $G_{0} = 1 / t (1 - 1 / 2 G^{2})$

$G_{0} = E (1 - 1 / 2 G_{0}^{2})$ $G_{0} = E (1 - 1 / 2 G_{0}^{2})$

$G_{0} = E (- 1 - 1 / 2 G_{0}^{2})$ $G_{0} = E (- 1 - 1 / 2 G_{0}^{2})$

$G_{0} t = (- 1 - 1 / 2 G_{0}^{2})$ $G_{0} t = (- 1 - 1 / 2 G_{0}^{2})$

$((1 / 2) G_{0}^{2}) - 1 - G t = 0$ $((1 / 2) G_{0}^{2}) - 1 - G t = 0$

$G_{0}^{2} - 2 G t - 1 = 0$ $G_{0}^{2} - 2 G t - 1 = 0$

For $t = 1 / 2 \to E_{m i n}$ $t = 1 / 2 \to E_{m i n}$

$G_{0}^{2} - G - 1 = 0$ $G_{0}^{2} - G - 1 = 0$

Golden Mean Parabola

F=Ma=-ks

$s = A (s i n (ω t + φ)$ $s = A (s i n (ω t + φ)$

Let $A = 1; ω = 1; t = 1$ $A = 1; ω = 1; t = 1$

$s = s i n θ$ $s = s i n θ$

But $s = E \times t = | E | | t | s i n θ$ $s = E \times t = | E | | t | s i n θ$

E=1=t

$s = s i n θ M a = - k s$

$117.33 (1 / \sqrt{2}) = - 0.4233 s i n θ$

$s i n θ = 196 = \infty$

$s i n 0.196 = 88.47 = ε_{0}$ Permitivity

Figure 1

Figure 1 Gravity and anti-gravity in balance.

Clairnaut

E-G=0

where

$G = d^{2} E / d t^{2}$

Ma=MG=118(6,52)=0.769

$θ = ω t + φ = 0.196$

$= 0.196 + π / 4$

=0.5839

t=1

$ω = \sqrt{0.5939}$

=0.7677

$ω = \sqrt{(k / M)}$

$α = (N - 1) δ / 2$

$α = π = (N - 1) π / 4 / 2$

$N = 9 = c^{2}$

So we have:

$E; t; s; M; ε_{0}; G_{0}; k; ω$

$δ (v = a); θ a n d c^{2}$

Conclusion

We see that the Surperforce acts on the exterior universe producing resonance effects.^3,4 The characteristic equation results, as well as mass of the proton and the periodic table of the elements mass.