In this brief paper, we provide some calculations from Wave mechanics, namely Resonance. We see that the universe is stoked by the superforce, and that energy is dampened by the mass. When taken with gravity, the characteristic equation for the universe results.

Keywords: superforce, astrotheology, resonance, golden mean equation

Using variables calculated in this author’s previous papers, we derive the characteristic equation for the universe working with the formulas that are used to determine resonance conditions.^1,2

$tan\delta =\left[1/Q\right]/\left[\left({\omega }_0/\omega \right)-\left(\omega /{\omega }_0\right)\right]$

$\delta =\pi /4$ (phase angle)

Q=1/2

Therefore $\omega ={\omega }_0=1$

$A=F_0/k{\left\{\left[\omega {\omega }_0\right]/{\left[\left({\omega }_0/\omega \right)-\left(\omega /{\omega }_0\right)\right]}^2+\left(1/Q^2\right)]\right\}}^{1/2}$

F=8/3

k=0.4233

$\omega ={\omega }_0=1$

Q=1/2

Therefore $A=125.99\sim 126=E_{min}$

$E_{min}1587=1-sin1=Moment.$

1-0.1587=8425

1/0.8425=118.87 = Mass Periodic Table of the elements.

${\omega }_m=\left(1\right){\left(1-1/{\left[2\left(1/2\right)\right)}^2\right]}^{1/2}$

$=\sqrt{(-1)}$

=-0.618

${\omega }_0<{\omega }_m$ 

Therefore, $\alpha =\pi$

$A_m=A_0=1/2/\left[1-4{\left(1/2\right)}^2\right]$

$=A_{0}1/0$

$=\infty$

${\omega }_m={\omega }_0{\{1-1/\left(2Q^2\right)]}^{1/2}$

${\omega }_m/{\omega }_0=0.935$

=mp+

$A_m=A_0\left[Q\right]/{\left[1-1/4Q^2\right]}^{1/2}$

$A_m/A_0=2.06$

$=\gamma$

=dM/dt

$\omega /{\omega }_0={\left(1-1/2Q^2\right)}^{1/2}$

=0.935

$=1-1/2Q^2={\left(\mathrm{0.938.7}\right)}^2$

$1-1/2Q^2=88.12$

$1/2Q^2=118.72$

$1/Q^2=23.65$

$Q=0/.1537=1/6.5=1/G$

$Q=0.1537=1/6.50~1/G_0$

${\omega }_m/{\omega }_0=\left(1-1/2{\text{ G}}^2\right)=Mp+$

$G_0/\left|Det.\right|=\sqrt{3}\sqrt{MP+}$

$G_0/Mp+=\left|D\right|\sqrt{3}$

$\left|D\right|=4$

$G_0/Mp+=6928\left(938\right)=6.50\sim G_0$

$1/6.928=1443=1-Ln\pi$

$G_0=\{1/\left(1-Ln\pi \right)]Mp+$

$1/\left(1-Ln\pi \right)=1/-t=-E$

$G_0=1/t\left(1-1/2G^2\right)$

$G_0=E\left(1-1/2G_0^2\right)$

$G_0=E\left(-1-1/2G_0^2\right)$

$G_{0}t=\left(-1-1/2G_0^2\right)$

$(\left(1/2\right)G_0^2)-1-Gt=0$

$G_0^2-2Gt-1=0$

For $t=1/2\to E_{min}$

$G_0^2-G-1=0$

Golden Mean Parabola

F=Ma=-ks

$s=A(sin\left(\omega t+\phi \right)$

Let $A=1;\omega =1;t=1$

$s=sin\theta$

But $s=E\times t=\left|E\right|\left|t\right|sin\theta$

E=1=t

$s=sin\theta Ma=-ks$

$117.33\left(1/\sqrt{2}\right)=-0.4233sin\theta$

$sin\theta =196=\infty$

$sin0.196=88.47={\epsilon }_0$ Permitivity

Figure 1

Figure 1 Gravity and anti-gravity in balance.

Clairnaut

E-G=0

where 

$G=d^{2}E/d{t}^2$

Ma=MG=118(6,52)=0.769

$\theta =\omega t+\phi =0.196$

$=0.196+\pi /4$

=0.5839

t=1

$\omega =\sqrt{0.5939}$

=0.7677

$\omega =\sqrt{\left(k/M\right)}$

$\alpha =\left(N-1\right)\delta /2$

$\alpha =\pi =\left(N-1\right)\pi /4/2$

$N=9=c^2$

So we have:

$E;t;s;M;{\epsilon }_0;G_0;k;\omega$

$\delta \left(v=a\right);\theta and{c}^2$

We see that the Surperforce acts on the exterior universe producing resonance effects.^3,4 The characteristic equation results, as well as mass of the proton and the periodic table of the elements mass.

None.

The author declares that there is no conflict of interest.

1. Cusack PTE. Astrotheology, Cusack’s Universe. J of Physical Math. 2016;7(2):8.
2. French AP. Vibrations and Waves.MIT Press. Norton. 1971;316.
3. Cusack PTE. The Light and the Ether.
4. Cusack P. Black Holes and Astrotheology II. Medcrave. 2018;1(4):143‒146.