In this article we consider the origin and subsequent evolution of our planet. Theoretical studies are based on the author's theory of vortex gravity, cosmology and cosmogony, and also on the law of conservation of the angular momentum of the body's rotation. As a practical justification for calculations and conclusions, the well-known fact of slowing the rotation of the Earth is used. The principles of the formation of elementary particles and all types of inorganic and organic substances are proposed. The calculation of the physical state of our planet in the past and in the future is done. The age of the Earth is calculated in the article, which exceeds the generally accepted value by 1.2 billion years. It is shown that the principle of the origin and evolution of the Earth is fully applicable for the genesis of all other celestial bodies.

Keywords: theory of vortex gravitation, celestial mechanics, cosmology, cosmogony

From the earliest ages people believed that the Earth's rotation around its axis and revolves around the Sun has always happened and is happening always in identical periods. Doubts about the constancy of the speed of rotation of the earth arose after the discovery of E Halley in 1695 secular acceleration of the moon's motion. The idea of ​​the secular slowing rotation of the Earth under the influence of tidal friction was first proposed by Kantin 1755 Nowadays Richard Stephenson from Durham University in the UK, based on the descriptions of hundreds of solar and lunar eclipses last 2,700years, came to the conclusion that the Earth continues slow.¹ Cause slowing of the Earth is called by many factors. These include the gravitational influence of the moon and sun, braking cosmic dust, atmospheric and geophysical processes and many other physical phenomena. In this paper, conventional explanations irregular rotation of the earth understood as an unproven and (or) is negligibly small. External gravitational influences or atmospheric effects cannot only slow, but also accelerate the Earth's rotation. The genesis of our planet, including the slowing of its rotation, fully explained by the theory of vortex gravitation, cosmology and cosmogony² and the laws of mechanics. For greater clarity, the readers, the next chapter outlines the principles of the theory of vortex gravitation.

Vortex gravitation theory2is based on the well-known astronomical facts-all celestial objects revolve. The most logical explanation of the cause of this movement can be only one - the rotation of celestial objects spawned vortex rotation of cosmic matter–ether. Ether forms a global system of interconnected space vortices. Orbital velocity in each vortex ether (torsion), decreasing from the center to the periphery of the law of the inverse square of the removal. According to the laws of aerodynamics-the slower the rate, the more pressure there. The pressure gradient gene rates a force pushing towards the zone with the lowest pressure to the center of the torsion bar (Figure 1). Thus accumulates in the center of the torsion or created cosmic matter of which is generated by celestial body. Consider the equation of vortex gravitation theory obtained in the theory of vortex gravitation, cosmology and cosmogony. Shown forces acting on the body 2. F_c-centrifugal force F_n-attraction force of body 2 to body 1, v₂-linear velocity of a body in orbit 2, R - radius of the orbit, r₁ - radius of the body1, r₂-radius of the body 2, w₁ -the angular velocity of rotation of the ether on the surface of the body1, m₂ - mass of the body 2. As already mentioned, the result of motion of the vortex pressure gradient arises. Radial distribution of pressure and velocity in the ether² defined on the basis of the Navier-Stokes equations for the motion of a viscous fluid (gas).

Figure 1 Two-dimensional model of the gravitational interaction between the two bodies.

Shown forces acting on the body2. F_c-centrifugal force F_n-attraction force of body 2tobody 1, v₂-linear velocity of a body in orbit2, R - radius of the orbit, r₁ - radius of the body1, r₂ - radius of the body2, w₁ -the angular velocity of rotation of the ether on the surface of the body1, m₂ - mass of the body2. As already mentioned, the result of motion of the vortex pressure gradient arises. Radial distribution of pressure and velocity in the ether² defined on the basis of the Navier-Stokes equations for the motion of a viscous fluid (gas).

$\rho \left[\frac{\partial }{\partial t}+\overrightarrow{v}\cdot grad\right]\overrightarrow{v}=\overrightarrow{F}-grad{\rm P}+\eta \Delta \overrightarrow{v}$  (1)

In cylindrical coordinates, taking into account the radial symmetry vr = vz =0 = v (r), P = P (r)j, equation can be written as a system.

$\{\begin{array}{l}-\frac{v{(r)}^2}{r}=-\frac{1}{\rho }\frac{dP}{dr}\\ \eta \cdot (\frac{{\partial }^{2}v(r)}{\partial r^2}+\frac{\partial v(r)}{r\partial r}-\frac{v(r)}{r^2})=0\end{array}$  (2)

Where $\rho =8.85x{10}^{-12}kg/m^3$ the density of,⁴ V-ether velocity vector, P – pressure ether, h -viscosity.

In cylindrical coordinates module gravity

$F_{п}=V\cdot \frac{\partial {\rm P}}{\partial r}$  (3)

Then comparing (2) and (3) for an in compressible there (r = const), we find that

$R_{-1}=6,371\times 10^6\times 0,94=5,988\times 10^6м$              (4)

The assumption № 1 – Ether pervades all space, including the physical body except nucleons. Volume V in the formula (4) an effective volume the volume of the elementary particles that make up the body 2. All bodies are composed of electrons, protons and neutrons. Radius of the electron is much smaller than the radius of the proton and the neutron radius is approximately the same and the last of the order $r_n~1.2\times {10}^{-15}m$  masses of the proton and neutron are approximately the same as $m_n~1.67\times {10}^{-27}kg$  (rn, mn - the radius and mass of the nucleon).

After the necessary transformation (full payment is set out in the theory vortex gravitation) is obtained:

1) Equation for determining the force of gravity depending on the rotational speed ether

$F_{п}=\frac{4\cdot \pi \cdot r_n{}^3\cdot \rho }{3\cdot m_n}\cdot \frac{w_1{}^2\cdot r_1{}^3\cdot m_2}{r^2}$   (5)

r_n, m_n -the radius and mass of the nucleon.

2) Equations for determining the dependence of the pressure on the body surfaceP₀,the rotational speed ether

${{\rm P}}_0={{\rm P}}_b-\rho \cdot w_1{}^2\cdot r_1{}^2$   (6)

Where P₀ - ether pressure at the surface of the body, using the boundary condition

P_b-free ether pressure. Figure 2 is a graph showing the pressure distribution in accordance with formula (6).

According to the theory of vortex gravitation, cosmology and cosmogony, the initial moment of the appearance of any celestial body was the emergence of space, ether vortex. At the time of its inception, each vortex created his vortex gravity (Chapter 2). Vortex gravity can be regarded as “generator world of matter “that sucks and (or) creates a vortex inside the elementary particles. Thus, the mass of each celestial object in the initial moment of its existence was equal to the mass of the cosmic ether, from which it was formed vortex. Since the density of the ether is negligible, then the mass of each of the newly formed vortex ether should be close to zero. Consequently, each celestial body in the history of its existence increased its weight from "zero conditional" to these values. It is worth noting an important condition - cosmic whirlwind unopposed, constantly maintained and retains its original speed (see assumption. № 1). Therefore, the space whirlwind constantly generates the same mass of substance. That is any celestial body increases the weight by a constant. Modern studies customary are slowing the Earth's rotation value 0.00002 seconds in each year.¹ Then the relative increase in time for the Earth's rotation around its axis is increased by a factor K_t.

${{\rm K}}_t=\left(24\times 60\times 60+0,00002\right)\times {\left(24\times 60\times 60\right)}^{-1}=1+2,314\times 10^{-10}$  

By increasing the time for one revolution of the earth is inversely proportional to the rotational speed decreases V_e. Then the relative decrease in the rate of rotation of K_v can be expressed as

$Кv={\rm K}{t}^{-1}={(1+2,314\times 10^{-10})}^{-1}$  (7)

Further calculations are based on the law of conservation of angular momentum the Earth's rotation around its axis.

$M{V}_v{R}_e$  = const  (8)

M=mass of the planet, V_v=the speed of rotation of the planet and R_e=the radius of the planet.

From equation (8)

$M{V}_v{R}_e=\left(K_{m}M\right)\left(K_{vv}{V}_v\right)\left(K{r}_e{R}_e\right)$  = const

Where the coefficients K_m, K_vv, K_re are show the relative changes in the values​​M, V_v, R_e.

Hence

$K_{m}K{v}_v K{r}_e=1$  (9)

Substituting (7) into (9) we obtain

${{\rm K}}_m{{\rm K}}_{re}=1+2,314\times 10^{-10}$  (10)

Planet mass(M),as well asits volume(V)is proportionalto the radius ofthe planetin the cube.

$M~V~R{e}^3$  here

$K{r}_e{}^3=K_m$  (11)

Substituting (11) into (10)

${{\rm K}}_r{}^4=1+2,314\times 10^{-10}$ or

${{\rm K}}_r={\left(1+2,314\times 10^{-10}\right)}^{1/4}=1+5,785\times 10^{-11}$  (12)

Substituting (12) into (10) we determine the relative increase in the mass of the Earth–

${{\rm K}}_m=1+1,735\times 10^{-10}$  (13)

To determine the absolute values ​​of the physical characteristics of the earth

1. At rotation speed of the Earth surface at the equator $V_v=465,1m/s$ , annual slowdown will

$465,1\times 2,314\times 10^{-10}=9,3\times 10^{-8}м/se\kappa$  (14)

2. When the radius of the Earth $Re=6371000$  manual increase in the radius of the Earth

$6371000\times 5,785\times 10^{-11}=3,7\times 10^{-4}мили0,37мм/year$  (15)

Or 37 cm in 1,000 years or 370m1 000 000years

Therefore, the earth deposits at a depth of about 370m have and average age of the sediments million years ago.

3. When the mass of the Earth $M=5.9736\times {10}^{24}$  kg annual weight gain

$5,9736\times 10^{24}\times 1.735\times 10^{-10}=1,036\times 10^{15}\kappa g$  (16)

Increased Earth The surface area of ​​the Earth $S_v=4M{R}^2$ .Increasing the radius of$-3.7x{10}^{-4}$ m

then the volume of the Earth increases by

$4ПR^2\times 3,7\times 10^{-4}=4х3.14\times {\left(6,371\times 10^6\right)}^2\times 3,7\times 10^{-4}=1,886\times 10^{11}{м}^3$   (17)

4. Additional mass density

${\rm P}=3,456\times 10^{14}\times {\left(1,835\times 10^{11}\right)}^{-1}=1883\kappa g/{м}^3$  (18)

Note: The absolute value ​​of the above characteristics of the Earth is only valid in the present historical moment, as the speed, radius and mass of the planet are constantly changing.

Earth's mass is constantly increasing the amount of (13)

$K_m=1.735x10^{-10}xM$

No outside forces act on the planet. Therefore, legitimate to use the law of conservation of angular momentum of the Earth around the Sun.

$M{V}_o{R}_o=const$ , where

$K_m{K}_{vo}{K}_{ro}=1$  (19)

M -mass of the Earth

V_o -the orbital speed of the Earth

R_o -radius of Earth's orbit.

K_m, K_vo, K_ro - rate of change in the Earth's mass units, the speed of its revolution around the Sun and the orbit radius.

According to Kepler's law$V~R_o{}^{-1/2}$ , we can write

$K_{vo} =K_r{}^{-1/2}$  (20)

Substitute (20) into (19)

${{\rm K}}_{ro}={{\rm K}}_m{}^{-2}={\left(1+1.735\times 10^{-10}\right)}^{-2}={\left(1+3,47\times 10^{-10}\right)}^{-1}$  (21)

Substituting (21) and (13) into equation (19) we obtain

${\rm K}{v}_o={({\rm K}mx{\rm K}{r}_o)}^{-1}=\left(1+3,47\times 10^{-10}\right)\times {\left(1+1.735\times 10^{-10}\right)}^{-1}=1+1.735\times 10^{-10}$  (22)

Mass of the planet increases always constant. Therefore, by dividing the mass of the Earth on its permanent annual increase $({\rm M}\times 1.735\times 10^{-10})$ , we obtain the age of the planet

${\rm T}={\rm M}\times {({\rm M}\times {\rm K}m)}^{-1}={\rm M}\times {({\rm M}\times 1.735\times 10^{-10})}^{-1}={\left(1,735\times 10^{-10}\right)}^{-1}=5,76$  billion years Radio isotope dating [3] established the age of the planet size of 4.54 billion years. It should be noted that the radioisotope dating explored only the surface layers of the planet. Therefore, the results of these studies (age) can be attributed only to the same surface layers.

The proposed method of determining the age of the planet considering as a single physical object, which increases the reliability of its results.

Annual approaching the Earth's orbit to the Sun

$R_o\times {{\rm K}}_{ro}=15х10^{10}\times 3,47\times 10^{-10}=52,05m/year$ And One revolution of the Earth around the sun(one year)is reduced by: $365,24(day)\times 24\times 60\times 60\times 1,735\times 10^{-10}=0,0054\sec /year$  

Calculation of physical properties in the past and in the future.

1 000 000 000 years ago

1. The rotation of the planet

Mass of the planet billion years ago $1,036x{10}^{15}(kg)x(4.76x{10}^9)\left(s\right)=4.93x{10}^{24}kg$

Mass ratio $K_{m-}{}_1=4.93x1024/5,97x1024=0,826$  

The relative change Earth radius $K_{r-}{}_1={(K_{m-}{}_1)}^{1/3}={\left(o,826\right)}^{1/3}=0.94$

From equation (19), $K_{v-}{}_1={(K_{r}x{K}_{m-}{}_1)}^{-1}={(0.826x0.94)}^{-1}=1.288$  Absolute values ​​of the planet a billion years ago. Since the velocity of the planet was more than1,288 times, in Length of day a billion years ago-18.6hours

Radius of the planet was less than0.94times or

$K_{r0-1}=1.466$ .

Consequently, the force of gravity was greater in ${\left(0.94\right)}^{-1/2}={\left(0.88\right)}^{-1}$ times. That is $m_n~1.67\times {10}^{-27}kg$

Handling the planet

Using formulas 20, 21,22 and $K_{m-}{}_1=0.826$ , we find:

- The ratio of the radii of ${{\rm K}}_{r0-1}=1.466$

-The relative decrease in orbital velocity (1billion years ago) –

${{\rm K}}_{vо-1}=0,826$

-The orbital speed $V_{0-1}=29,8\times 10^3\times 0,826=24,6\times 10^{3}m/s$

- The ratio of the radius

$R_{o-1}=R\times {{\rm K}}_{ro-1}=15\times 10^{10}\times 1,466=219,9m\ln \kappa m$

The number of days (18.6 hours).Per revolution (one year)-838,4 days.

After1 000 000 000years in the future

1. The rotation of the planet

Mass of the planet a billion years $1,036\times 10^{15}\left(kg\right)\times 6,76\times 10^9\left(years\right)=7,0\times 10^{24}\kappa g$

Changing the masses ${{\rm K}}_{m+1}=7,0\times 10^{24}/5,97\times 10^{24}=1,173$

The relative change radius of the Earth ${{\rm K}}_{r+1}={\left({{\rm K}}_{m+1}\right)}^{1/3}={\left(1,173\right)}^{1/3}=1,055$

From equation (19), ${{\rm K}}_{v+1}={\left({{\rm K}}_{r+1}\times {{\rm K}}_{m+1}\right)}^{-1}={\left(1,055х1,173\right)}^{-1}=0,81$

The absolute values ​​of the properties of the planet in the future in a billion years.

Since the rotation speed of the planets will be less than0.81times, then

Length of the day 29.6hours

Radius of the planet $R_{+1}=6,721x{10}^{6}m$

The gravitational force $F=8,8m$

2. Handling the planet

Using formulas 20, 21,22 and ${{\rm K}}_{m+1}=1,173$ ,we find:

The relative increase in orbital velocity(in billion years in the future)

${{\rm K}}_{vо+1}=1,042$

Relation of orbital radiuses ${{\rm K}}_{ro+1}=0,727$

Radius of the orbit $R_v{}_{o+1}=Rx{K}_{ro+1}=15x10^{10}x0,727=109mlnkm$

The orbital speed of $V_0+1=29.8x103x1,042x103=31.05m/s$

Number of days (29.6 hours) per revolution (year) -206.9

Note 1: The proposed calculations of the radius of Earth’s orbit are valid only if the orbital plane is considered a celestial body (the Earth) coincides with the center plane of the gravitational ether vortex. In the event of the orbital plane of the celestial body of the plane gravitational torsion vortex gravitation force is reduced in proportion to the cube of the cosine of the deviation. A detailed calculation of this dependence is presented in the theory of vortex gravitation. Orbital plane of the Earth's gravity deviates from the plane by degree. Consequently, the tops of the small semi axes earth orbit force swirl solar gravity decreases by 0.045% in comparison with the magnitude of gravity, which was determined by the classical equations. Therefore, changing the radius of the orbit of the Earth or the duration of the year in the past or the future, calculated in this article actually has smaller values. For large deviations of the orbital planes of any celestial object and the long duration of their existence can remove the orbital trajectories of these objects from the call center. Such removal (38mm per year) is currently seen in the moon.

None.

Authors declare that there are no conflicts of interests.

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